Input numbers in 2d array and find the sum of each row, column, right and left diagonal in C++

Two Dimensional Array - Question 7

In this question, we will see how to input numbers in a 3X3 integer matrix (2d array) and find the sum of each row, each column, right diagonal and left diagonal separately in C++ programming. To know more about two dimensional array click on the two dimensional array lesson.

Q7) Write a program in C++ to input numbers in a 3X3 integer matrix (2d array) and find the sum of each row, each column, right diagonal and left diagonal separately. Right Diagonal = / and Left Diagonal = \.

Program

``````#include <iostream>
#include <conio.h>

using namespace std;

int main()
{
int a[3][3], r,c,rs,cs,rd=0,ld=0;

cout<<"Enter 9 numbers\n";
for(r=0; r<3; r++)
{
for(c=0; c<3; c++)
{
cin>>a[r][c];
}
}

for(r=0; r<3; r++)
{
rs=0;
cs=0;
ld=ld+a[r][r];
rd=rd+a[r][2-r];
for(c=0; c<3; c++)
{
cout<<a[r][c]<<" ";
rs=rs+a[r][c];		// row sum
cs=cs+a[c][r];		// column sum
}
cout<<"  Row Sum = "<<rs<<"  Column Sum = "<<cs<<endl;
}
cout<<"Left Diagonal Sum = "<<ld<<endl;
cout<<"Right Diagonal Sum = "<<rd;
return 0;
}``````

Output

```Enter 9 numbers
18
12
72
10
15
45
38
5
64
18 12 72   Row Sum = 102  Column Sum = 66
10 15 45   Row Sum = 70  Column Sum = 32
38 5 64   Row Sum = 107  Column Sum = 181
Left Diagonal Sum = 97
Right Diagonal Sum = 125```