Input numbers in 2d array and find the sum of each row, column, right and left diagonal in C++
Two Dimensional Array - Question 7
In this question, we will see how to input numbers in a 3X3 integer matrix (2d array) and find the sum of each row, each column, right diagonal and left diagonal separately in C++ programming. To know more about two dimensional array click on the two dimensional array lesson.
Q7) Write a program in C++ to input numbers in a 3X3 integer matrix (2d array) and find the sum of each row, each column, right diagonal and left diagonal separately. Right Diagonal = / and Left Diagonal = \.
Program
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int a[3][3], r,c,rs,cs,rd=0,ld=0;
cout<<"Enter 9 numbers\n";
for(r=0; r<3; r++)
{
for(c=0; c<3; c++)
{
cin>>a[r][c];
}
}
for(r=0; r<3; r++)
{
rs=0;
cs=0;
ld=ld+a[r][r];
rd=rd+a[r][2-r];
for(c=0; c<3; c++)
{
cout<<a[r][c]<<" ";
rs=rs+a[r][c]; // row sum
cs=cs+a[c][r]; // column sum
}
cout<<" Row Sum = "<<rs<<" Column Sum = "<<cs<<endl;
}
cout<<"Left Diagonal Sum = "<<ld<<endl;
cout<<"Right Diagonal Sum = "<<rd;
return 0;
}Output
Enter 9 numbers 18 12 72 10 15 45 38 5 64 18 12 72 Row Sum = 102 Column Sum = 66 10 15 45 Row Sum = 70 Column Sum = 32 38 5 64 Row Sum = 107 Column Sum = 181 Left Diagonal Sum = 97 Right Diagonal Sum = 125
