Input number and check perfect number or not using while loop in C++

while Loop - Question 8

Q8) Write a program in C++ to input a number and check if it is a perfect number or not using while loop.

A Perfect number is a number, whose sum of the factors excluding the given number itself is equal to the given number.

Example: Sum of factors of 6 excluding 6 is 1+2+3 which is equal to 6, so 6 is a perfect number.

#include <iostream>
#include <conio.h>

using namespace std;

int main()
{
    int i=1,n,sf=0;

    cout<<"Enter a number ";
    cin>>n;

    while(i<n)
    {
        if(n%i==0)
        {
            sf=sf+i; 		// sum of factors
        }
        i=i+1;
    }

    if(sf==n)
    {
        cout<<"Perfect Number";
    }
    else
    {
        cout<<"Not Perfect Number";
    }
    return 0;
}

Enter a number 28
Perfect Number