# Input number and find sum of all odd and even digits in it using for loop in C++

###### for Loop - Question 12

In this question, we will see how to input a number and find the sum of all odd digits and even digits present in the number separately in C++ programming using for loop. To know more about for loop click on the for loop lesson.

**Q12)** Write a program in C++ to input a number and find the sum of all odd digits and even digits present in the number separately using for loop.

#### Program

```
#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
int i,n,d,even=0,odd=0;
cout<<"Enter a number ";
cin>>n;
for(i=n; i>0; i=i/10)
{
d=i%10;
if(d%2==0)
{
even=even+d;
}
else
{
odd=odd+d;
}
}
cout<<"Sum of even digits = "<<even<<endl;
cout<<"Sum of odd digits = "<<odd;
return 0;
}
```

#### Output

Enter a number 45612 Sum of even digits = 12 Sum of odd digits = 6