Input number and find sum of all odd and even digits in it using for loop in C
for Loop - Question 12
In this question, we will see how to input a number and find the sum of all odd digits and even digits present in the number separately in C programming using for loop. To know more about for loop click on the for loop lesson.
Q12) Write a program in C to input a number and find the sum of all odd digits and even digits present in the number separately using for loop.
Program
#include <stdio.h>
#include <conio.h>
int main()
{
int i,n,d,even=0,odd=0;
printf("Enter a number ");
scanf("%d",&n);
for(i=n; i>0; i=i/10)
{
d=i%10;
if(d%2==0)
{
even=even+d;
}
else
{
odd=odd+d;
}
}
printf("Sum of even digits = %d\n",even);
printf("Sum of odd digits = %d",odd);
return 0;
}Output
Enter a number 45612 Sum of even digits = 12 Sum of odd digits = 6
