Input a number and check if it is a special two-digit number or not using a function in C++
Function - Question 6
In this question, we will see how to input a number and check if it is a special two-digit number or not in C++ programming using a function. To know more about function click on the function lesson.
Q6) Write a program in C++ to input a number and check if it is a special two-digit number or not using a function. The function should return 1 if the numbers is a special two-digit number else return 0.
A special two-digit number is such that when the sum of its digits is added to the product of its digits, the result is equal to the original two-digit number.
Example: 59 is a special two-digit number. Sum of its digits 5+9 = 14 Product of its digit 5*9 = 45 Sum of sum and product of the digits 14+45 = 59
Program
#include <iostream>
#include <conio.h>
using namespace std;
int specialnumber(int num)
{
int s=0,p=1,t,d;
t=num;
if(t>=10 && t<=99)
{
while(t>0)
{
d=t%10;
s=s+d; // sum of digits
p=p*d; // product of digits
t=t/10;
}
if(s+p==num)
{
return 1;
}
}
return 0;
}
int main()
{
int n;
cout<<"Enter a number ";
cin>>n;
if(specialnumber(n)==1)
{
cout<<"Special Two Digit Number";
}
else
{
cout<<"Not Special Two Digit Number";
}
return 0;
}Output
Enter a number 59 Special Two Digit Number
