 # Input a number and check if it is an armstrong number or not using a function in C++

###### Function - Question 8

In this question, we will see how to input a number and check if it is an Armstrong number or not in C++ programming using a function. To know more about function click on the function lesson.

Q8) Write a program in C++ to input a number and check if it is an Armstrong number or not using a function. The function should return 1 if the numbers is an Armstrong number else return 0. An Armstrong number is a number whose sum of the cube of its digit is equal to the number itself.

Example 153 = 13+53+33

#### Program

``````#include <iostream>
#include <conio.h>

using namespace std;

int armstrong(int num)
{
int s=0,t,d;
t=num;
while(t>0)
{
d=t%10;
s=s+(d*d*d);     // sum of cube of the digits
t=t/10;
}

if(s==num)
{
return 1;
}
return 0;
}

int main()
{
int n;
cout<<"Enter a number ";
cin>>n;
if(armstrong(n)==1)
{
cout<<"Armstrong Number";
}
else
{
cout<<"Not Armstrong Number";
}
return 0;
}``````

#### Output

```Enter a number 153
Armstrong Number``` 